A small linux command line program that converts between bases
Useage:
Run the program, and enter the unit in one of 4 formats.
Binary: 0bxxxxxxxx
Hex: 0xXX
Octal: 0oXX
Deciaml:XX
Code:
[code land=“c”]
#include
#include
#include <readline/readline.h>
#include <readline/history.h>
#include <stdlib.h>
using namespace std;
void binary(long number) {
long remainder;
if(number <= 1) {
cout << number;
return;
}
remainder = number%2;
binary(number >> 1);
cout << remainder;
}
int main(){
char numbera[64];
long number;
char letter=-1;
while(1){
cout << “Enter a number: ”;
while((buf = readline(“\n >> ”))!=NULL)
{
if (strcmp(buf,“quit”)==0)
break;
printf(”[%s]\n”,buf);
if (buf[0]!=0)
add_history(buf);
}
strcpy(numbera,buf);
letter = numbera[1];
if (letter==-1)
cout <<“Error”<<endl;
else if (letter == ‘x’ | letter == ‘X’){
number=strtol(numbera,NULL,16);
}
else if(letter==‘o’ | letter == ‘O’){
numbera[1]=‘0’;
cout << numbera<<endl;
number=strtol(numbera,NULL,8);
}
else if(letter==‘b’ | letter == ‘B’){
numbera[1]=‘0’;
number=strtol(numbera,NULL,2);
}
else{
number=strtol(numbera,NULL,10);
}
cout << “Answer :“<<endl;
cout << “Hex:\t”<< hex <<number<<endl;
cout << “Oct:\t”<<oct <<number<<endl;
cout << “Dec:\t”<<dec <<number<<endl<<“Bin:\t”;
binary(number);
cout << endl<<endl<<endl;
}
free(buf);
return 0;
}
[/code]